3.14.22 \(\int \frac {a+b x}{(c+d x)^{3/2}} \, dx\)

Optimal. Leaf size=38 \[ \frac {2 (b c-a d)}{d^2 \sqrt {c+d x}}+\frac {2 b \sqrt {c+d x}}{d^2} \]

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Rubi [A]  time = 0.01, antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {43} \begin {gather*} \frac {2 (b c-a d)}{d^2 \sqrt {c+d x}}+\frac {2 b \sqrt {c+d x}}{d^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x)/(c + d*x)^(3/2),x]

[Out]

(2*(b*c - a*d))/(d^2*Sqrt[c + d*x]) + (2*b*Sqrt[c + d*x])/d^2

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int \frac {a+b x}{(c+d x)^{3/2}} \, dx &=\int \left (\frac {-b c+a d}{d (c+d x)^{3/2}}+\frac {b}{d \sqrt {c+d x}}\right ) \, dx\\ &=\frac {2 (b c-a d)}{d^2 \sqrt {c+d x}}+\frac {2 b \sqrt {c+d x}}{d^2}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 27, normalized size = 0.71 \begin {gather*} \frac {2 (-a d+2 b c+b d x)}{d^2 \sqrt {c+d x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)/(c + d*x)^(3/2),x]

[Out]

(2*(2*b*c - a*d + b*d*x))/(d^2*Sqrt[c + d*x])

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IntegrateAlgebraic [A]  time = 0.03, size = 29, normalized size = 0.76 \begin {gather*} \frac {2 (-a d+b (c+d x)+b c)}{d^2 \sqrt {c+d x}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(a + b*x)/(c + d*x)^(3/2),x]

[Out]

(2*(b*c - a*d + b*(c + d*x)))/(d^2*Sqrt[c + d*x])

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fricas [A]  time = 1.13, size = 35, normalized size = 0.92 \begin {gather*} \frac {2 \, {\left (b d x + 2 \, b c - a d\right )} \sqrt {d x + c}}{d^{3} x + c d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)/(d*x+c)^(3/2),x, algorithm="fricas")

[Out]

2*(b*d*x + 2*b*c - a*d)*sqrt(d*x + c)/(d^3*x + c*d^2)

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giac [A]  time = 1.03, size = 34, normalized size = 0.89 \begin {gather*} \frac {2 \, \sqrt {d x + c} b}{d^{2}} + \frac {2 \, {\left (b c - a d\right )}}{\sqrt {d x + c} d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)/(d*x+c)^(3/2),x, algorithm="giac")

[Out]

2*sqrt(d*x + c)*b/d^2 + 2*(b*c - a*d)/(sqrt(d*x + c)*d^2)

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maple [A]  time = 0.00, size = 26, normalized size = 0.68 \begin {gather*} -\frac {2 \left (-b d x +a d -2 b c \right )}{\sqrt {d x +c}\, d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)/(d*x+c)^(3/2),x)

[Out]

-2/(d*x+c)^(1/2)*(-b*d*x+a*d-2*b*c)/d^2

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maxima [A]  time = 1.33, size = 37, normalized size = 0.97 \begin {gather*} \frac {2 \, {\left (\frac {\sqrt {d x + c} b}{d} + \frac {b c - a d}{\sqrt {d x + c} d}\right )}}{d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)/(d*x+c)^(3/2),x, algorithm="maxima")

[Out]

2*(sqrt(d*x + c)*b/d + (b*c - a*d)/(sqrt(d*x + c)*d))/d

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mupad [B]  time = 0.05, size = 25, normalized size = 0.66 \begin {gather*} \frac {4\,b\,c-2\,a\,d+2\,b\,d\,x}{d^2\,\sqrt {c+d\,x}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x)/(c + d*x)^(3/2),x)

[Out]

(4*b*c - 2*a*d + 2*b*d*x)/(d^2*(c + d*x)^(1/2))

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sympy [A]  time = 0.61, size = 60, normalized size = 1.58 \begin {gather*} \begin {cases} - \frac {2 a}{d \sqrt {c + d x}} + \frac {4 b c}{d^{2} \sqrt {c + d x}} + \frac {2 b x}{d \sqrt {c + d x}} & \text {for}\: d \neq 0 \\\frac {a x + \frac {b x^{2}}{2}}{c^{\frac {3}{2}}} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)/(d*x+c)**(3/2),x)

[Out]

Piecewise((-2*a/(d*sqrt(c + d*x)) + 4*b*c/(d**2*sqrt(c + d*x)) + 2*b*x/(d*sqrt(c + d*x)), Ne(d, 0)), ((a*x + b
*x**2/2)/c**(3/2), True))

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